factoriza por el método de factor comun F(x)=(x-3)(x-2)-(x-2)(1-x)+1-x​

Respuesta:Explicación paso a paso:F(x)=(x-3)(x-2)-(x-2)(1-x)+1-x​F(x) = (x-2)[(x-3) - (1- x)]  + 1 -xF(x) = (x-2) [x-3-1+x] + 1 - xF(x) = (x - 2)(2x - 4) + 1 - xF(x) = (x-2)(x-2)*2 +1 - xF(x) = 2(x-2)^2 + 1 - xF(x) = 2(x^2 - 2x +4) + 1 -xF(x) = 2x^2 - 4x +8 + 1 - xF(X) = 2x^2 - 3x + 9F(X) = (2x - 3)(x - 3)

Answered by jacosta837 | 2025-08-07