Explicación paso a paso:4.[tex] {(x - 1)}^{2} + {(y + 3)}^{2} = {5}^{2} \\ [/tex]5.a)[tex] {x}^{2} - 6x + 9 + {y}^{2} - 8y + 16 \\ = 9 + 16 - 9 \\ {(x - 3)}^{2} + {(y - 4)}^{2} = {4 \\ }^{2} [/tex]C(3;4) y r=4b)p(2;1)[tex] {2}^{2} + {1}^{2} - 4(2) - 6(1) + 4 = 0 \\ 4 + 1 - 8 - 6 + 4 = 0 \\ - 5 = 0 \\ [/tex]no pertenece