A- (4x² - 2x) + (X+4) =
B- (6x⁴ - 2x² + 5x - 3) + (X-2) =
C- (X⁵ - 2x⁴ -X2 -x + 6) + (X -2) =
D- (2x³ - 2x² - 4x + 16) + (X + 2) =
Resuelvo estos ejercicios aplicando el Teorema del Resto.

Ejercicio A:A = (4x^2 - 2x) + (x + 4)A = 4x^2 + (-2x + x) + 4A = 4x^2 - x + 4 Ejercicio B:B = (6x^4 - 2x^2 + 5x - 3) + (x - 2)B = 6x^4 + (-2x^2) + (5x + x) + (-3 - 2)B = 6x^4 - 2x^2 + 6x - 5 Ejercicio C:C = (x^5 - 2x^4 - x^2 - x + 6) + (x - 2)C = x^5 + (-2x^4) + (-x^2) + (-x + x) + (6 - 2)C = x^5 - 2x^4 - x^2 + 4 Ejercicio D:D = (2x^3 - 2x^2 - 4x + 16) + (x + 2)D = 2x^3 + (-2x^2) + (-4x + x) + (16 + 2)D = 2x^3 - 2x^2 - 3x + 18 

Answered by perlitadanisa | 2025-08-11