x²+x-6=0 resultado porfow​

Respuesta:x²+x-6 = 0x²+x-6+6 = 0+6x²+x = 6x²+x+(1/2)² = 6+(1/2)²(x+(1/2))² = 25/4(x+(1/2))² = 25/4(x+(1/2))² = 25/4√(x+(1/2))² = ±√(25/4)x+(1/2) = ±(5/2)x+(1/2)-(1/2) = ±(5/2)-(1/2)x = ±(5/2)-(1/2)x₁ = -(5/2)-(1/2)x₁ = -6/2x₁ = - 3x₂ = (5/2)-(1/2)x₂ = 4/2x₂ = 2Verificación con '' x₁ = - 3 '' :(-3)²+(-3)-6 = 09-3-6 = 09-(3+6) = 09-9 = 00 = 0Comprobación con '' x₂ = 2 '' :(2)²+(2)-6 = 04+2-6 = 04+(2-6) = 04+(-4) = 04-4 = 00 = 0R// Por ende , las raíces o soluciones de la ecuación de segundo grado '' x²+x-6 = 0 '' son '' x₁ = - 3 '' y '' x₂ = 2 '' .

Answered by darwinstevenva46 | 2025-08-15