In Matemáticas / Bachillerato | 2025-08-20
Asked by alexiajana26
Respuesta:Solve by elimination:(1) 3x + 2y = 16(2) 5x − 3y = −5Multiply (1) by 3 → 9x + 6y = 48Multiply (2) by 2 → 10x − 6y = −10Add them → 19x = 38 → x = 2Plug back into (1): 3(2) + 2y = 16 → 6 + 2y = 16 → 2y = 10 → y = 5Answer: x = 2, y = 5. ✅
Answered by poteslunajeremy | 2025-08-20