E = (1 + y) (1 - y + y²) - y³ayudenme pls :(
Answer (1)
Respuesta:E = (1+y)(1-y+y²)-y³E = 1(1-y+y²)+y(1-y+y²)-y³E = (1-y+y²)+y-y²+y³-y³E = (1-y+y²)+(y-y²+y³)-y³E = 1+(-1+1)y+(1-1)y²+(1-1)y³E = 1+0+0+0E = 1R// El valor de la expresión '' E = (1 + y) (1 - y + y²) - y³ '' es 1 .
