7sin(x)+2-4sin(x)=1
Resolver la ecuacion

Respuesta:7sen(x)+2-4sen(x) = 1(7-4)sen(x)+2 = 13sen(x)+2 = 13sen(x)+2-2 = 1-23sen(x) = - 1(1/3)×3sen(x) = -1×(1/3)sen(x) = -1/3arcsen(sen(x)) = arcsen(-1/3)x = arcsen(-1/3) ; arcsen(-1/3) ≈ - 19.4712 °x ≈ - 19.4712 °Verificación :7sen(-19.4712°)+2-4sen(-19.4712°) = 1 ; sen(-19.4712°) ≈ - 0.33337(-0.3333)+2-4sen(-19.4712°) = 1-2.3331+2-4(-0.3333) = 1-0.3331-(-4×0.3333) = 1-0.3331-(-1.3332) = 1-0.3331+1.3332 = 1 1.0001 ≈ 1 R// El valor del ángulo '' x '' es de alrededor de - 19.4712°

Answered by darwinstevenva46 | 2025-08-24