Y=(2x -1) (x² -6x+3) hallar derivada

Respuesta:Y = (2x-1)(x²-6x+3)Y = 2x(x²-6x+3)-(x²-6x+3)Y = 2x(x²)-2x(6x)+3(2x)-(x²)-(-6x)-(3)Y = 2x³-12x²+6x-x²+6x-3Y = 2x³-13x²+12x-3Y' = ((2x³-13x²+12x-3))'Y' = (2x³)'-(13x²)'+(12x)'-(3)'Y' = 2(x³)'-(13x²)'+(12x)'-(3)'Y' = 2(3x²)-(13x²)'+(12x)'-(3)'Y' = 6x²-(13x²)'+(12x)'-(3)'Y' = 6x²-13(x²)'+(12x)'-(3)'Y' = 6x²-13(2x)+(12x)'-(3)'Y' = 6x²-26x+(12x)'-(3)'Y' = 6x²-26x+12(x)'-(3)'Y' = 6x²-26x+12×1-(3)' Y' = 6x²-26x+12-0Y' = 6x²-26x+12R// La derivada de la función '' Y = (2x-1)(x²-6x+3) '' es '' Y' = 6x²-26x+12 ''

Answered by darwinstevenva46 | 2025-08-24