3log(y) = 3+log(y/10)

Aplicamos las propiedades de los logaritmos.Se trata de logaritmos de base 10.3 log(y) = log(y³)log(y/10) = log (y) - log(10)Reemplazamos.log(y³) = 3 + log (y) - log(10)Trasponemos términoslog(y³)  - log (y) + log(10) = 3log(10) = 1log(y³) - log(y) = log(y³/y) = log(y²)log(y²) = 3 - 1 = 2Finalmente y² = 10²y = 10

Answered by mateorinaldi | 2025-08-26